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		<title>feynman rules</title>
		<link>http://tally.wordpress.com/2010/10/14/feynman-rules/</link>
		<comments>http://tally.wordpress.com/2010/10/14/feynman-rules/#comments</comments>
		<pubDate>Thu, 14 Oct 2010 04:50:28 +0000</pubDate>
		<dc:creator>xil41</dc:creator>
				<category><![CDATA[notes]]></category>

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		<description><![CDATA[Convention: and . Consider . Using the identity, , we will have . as well as . Now, consider<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=tally.wordpress.com&amp;blog=376204&amp;post=88&amp;subd=tally&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>Convention:</p>
<p><img src='http://s0.wp.com/latex.php?latex=f%28x%29+%3D+%5Cfrac%7B1%7D%7B2%5Cpi%7D+%5Cint+%5Cmathrm%7Bd%7Dq+f%28q%29+e%5E%7B-iqx%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='f(x) = &#92;frac{1}{2&#92;pi} &#92;int &#92;mathrm{d}q f(q) e^{-iqx}' title='f(x) = &#92;frac{1}{2&#92;pi} &#92;int &#92;mathrm{d}q f(q) e^{-iqx}' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=f%28q%29+%3D+%5Cint+%5Cmathrm%7Bd%7Dx+f%28x%29+e%5E%7Biqx%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='f(q) = &#92;int &#92;mathrm{d}x f(x) e^{iqx}' title='f(q) = &#92;int &#92;mathrm{d}x f(x) e^{iqx}' class='latex' />.</p>
<p>Consider</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bi%7D%7B2%7Dg+%5Cint_%7B-%5Cinfty%7D%5E%7Bz%5E-%7D+%5Cmathrm%7Bd%7Dy%5E-+A%5E%2B%28y%5E-%29++%3D++%5Cfrac%7Bi%7D%7B2%7Dg+%5Cint_%7B-%5Cinfty%7D%5E%7B%2B%5Cinfty%7D+%5Cmathrm%7Bd%7Dy%5E-+A%5E%2B%28y%5E-%29+%5Ctheta%28z%5E--y%5E-%29+&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;frac{i}{2}g &#92;int_{-&#92;infty}^{z^-} &#92;mathrm{d}y^- A^+(y^-)  =  &#92;frac{i}{2}g &#92;int_{-&#92;infty}^{+&#92;infty} &#92;mathrm{d}y^- A^+(y^-) &#92;theta(z^--y^-) ' title='&#92;frac{i}{2}g &#92;int_{-&#92;infty}^{z^-} &#92;mathrm{d}y^- A^+(y^-)  =  &#92;frac{i}{2}g &#92;int_{-&#92;infty}^{+&#92;infty} &#92;mathrm{d}y^- A^+(y^-) &#92;theta(z^--y^-) ' class='latex' />.</p>
<p> Using the identity,</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7B-1%7D%7B2+%5Cpi+i%7D+%5Cint+%5Cmathrm%7Bd%7Ds+%5Cfrac%7Be%5E%7B-%5Cfrac%7Bi%7D%7B2%7D%28z%5E--y%5E-%29s%7D%7D%7Bs%2Bi%5Cepsilon%7D+%3D%5Ctheta%28z%5E--y%5E-%29&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;frac{-1}{2 &#92;pi i} &#92;int &#92;mathrm{d}s &#92;frac{e^{-&#92;frac{i}{2}(z^--y^-)s}}{s+i&#92;epsilon} =&#92;theta(z^--y^-)' title='&#92;frac{-1}{2 &#92;pi i} &#92;int &#92;mathrm{d}s &#92;frac{e^{-&#92;frac{i}{2}(z^--y^-)s}}{s+i&#92;epsilon} =&#92;theta(z^--y^-)' class='latex' />,</p>
<p>we will have</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bi%7D%7B2%7Dg+%5Cint_%7B-%5Cinfty%7D%5E%7Bz%5E-%7D+%5Cmathrm%7Bd%7Dy%5E-+A%5E%2B%28y%5E-%29++%3D+-g+%5Cint+%5Cfrac%7B%5Cmathrm%7Bd%7D%5E4q%7D%7B%282%5Cpi%29%5E4%7D+%5Cfrac%7BA%5E%2B%28q%29%7D%7Bq%5E%2B+%2B+i%5Cepsilon%7D+e%5E%7B-%5Cfrac%7Bi%7D%7B2%7Dq%5E%2B+z%5E-%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;frac{i}{2}g &#92;int_{-&#92;infty}^{z^-} &#92;mathrm{d}y^- A^+(y^-)  = -g &#92;int &#92;frac{&#92;mathrm{d}^4q}{(2&#92;pi)^4} &#92;frac{A^+(q)}{q^+ + i&#92;epsilon} e^{-&#92;frac{i}{2}q^+ z^-}' title='&#92;frac{i}{2}g &#92;int_{-&#92;infty}^{z^-} &#92;mathrm{d}y^- A^+(y^-)  = -g &#92;int &#92;frac{&#92;mathrm{d}^4q}{(2&#92;pi)^4} &#92;frac{A^+(q)}{q^+ + i&#92;epsilon} e^{-&#92;frac{i}{2}q^+ z^-}' class='latex' />.</p>
<p>as well as</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bi%7D%7B2%7Dg+%5Cint%5E%7B%5Cinfty%7D_%7Bz%5E-%7D+%5Cmathrm%7Bd%7Dy%5E-+A%5E%2B%28y%5E-%29++%3D+-g+%5Cint+%5Cfrac%7B%5Cmathrm%7Bd%7D%5E4q%7D%7B%282%5Cpi%29%5E4%7D+%5Cfrac%7BA%5E%2B%28q%29%7D%7B-q%5E%2B+%2B+i%5Cepsilon%7D+e%5E%7B-%5Cfrac%7Bi%7D%7B2%7Dq%5E%2B+z%5E-%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;frac{i}{2}g &#92;int^{&#92;infty}_{z^-} &#92;mathrm{d}y^- A^+(y^-)  = -g &#92;int &#92;frac{&#92;mathrm{d}^4q}{(2&#92;pi)^4} &#92;frac{A^+(q)}{-q^+ + i&#92;epsilon} e^{-&#92;frac{i}{2}q^+ z^-}' title='&#92;frac{i}{2}g &#92;int^{&#92;infty}_{z^-} &#92;mathrm{d}y^- A^+(y^-)  = -g &#92;int &#92;frac{&#92;mathrm{d}^4q}{(2&#92;pi)^4} &#92;frac{A^+(q)}{-q^+ + i&#92;epsilon} e^{-&#92;frac{i}{2}q^+ z^-}' class='latex' />.</p>
<p>Now, consider </p>
<p>    <img src='http://s0.wp.com/latex.php?latex=%7B%5Cbar+h%7D%28z%5E-%29+%5CPhi%28z%5E-%29+%5CPhi%5E%5Cdagger+%280%29+h%280%29&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='{&#92;bar h}(z^-) &#92;Phi(z^-) &#92;Phi^&#92;dagger (0) h(0)' title='{&#92;bar h}(z^-) &#92;Phi(z^-) &#92;Phi^&#92;dagger (0) h(0)' class='latex' /><br />
<img src='http://s0.wp.com/latex.php?latex=%3D+%5Cint+%5Cfrac%7B%5Cmathrm%7Bd%7Dq_1%7D%7B%282%5Cpi%29%5E4%7D+%5Cfrac%7B%5Cmathrm%7Bd%7Dq_2%7D%7B%282%5Cpi%29%5E4%7D+e%5E%7B%5Cfrac%7B-i%7D%7B2%7D%28q%5E%2B_1%2Bq%5E%2B_2%29z%5E-%7D%7B%5Cbar+h%7D%28q_1%29+%5CPhi%28q_2%29+%5Cint+%5Cfrac%7B%5Cmathrm%7Bd%7Dq_3%7D%7B%282%5Cpi%29%5E4%7D+%5Cfrac%7B%5Cmathrm%7Bd%7Dq_4%7D%7B%282%5Cpi%29%5E4%7D+%5CPhi%5E%5Cdagger+%28q_3%29+h%28q_4%29++&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='= &#92;int &#92;frac{&#92;mathrm{d}q_1}{(2&#92;pi)^4} &#92;frac{&#92;mathrm{d}q_2}{(2&#92;pi)^4} e^{&#92;frac{-i}{2}(q^+_1+q^+_2)z^-}{&#92;bar h}(q_1) &#92;Phi(q_2) &#92;int &#92;frac{&#92;mathrm{d}q_3}{(2&#92;pi)^4} &#92;frac{&#92;mathrm{d}q_4}{(2&#92;pi)^4} &#92;Phi^&#92;dagger (q_3) h(q_4)  ' title='= &#92;int &#92;frac{&#92;mathrm{d}q_1}{(2&#92;pi)^4} &#92;frac{&#92;mathrm{d}q_2}{(2&#92;pi)^4} e^{&#92;frac{-i}{2}(q^+_1+q^+_2)z^-}{&#92;bar h}(q_1) &#92;Phi(q_2) &#92;int &#92;frac{&#92;mathrm{d}q_3}{(2&#92;pi)^4} &#92;frac{&#92;mathrm{d}q_4}{(2&#92;pi)^4} &#92;Phi^&#92;dagger (q_3) h(q_4)  ' class='latex' /><br />
<img src='http://s0.wp.com/latex.php?latex=%3D+%5Cint+%5Cmathrm%7Bd%7D%5Comega+e%5E%7B%5Cfrac%7B-i%7D%7B2%7D%5Comega+z%5E-%7D++%5Cint+%5Cprod_%7Bi%3D1%7D%5E%7B4%7D+%5Cfrac%7B%5Cmathrm%7Bd%7D%5E4q_i%7D%7B%282%5Cpi%29%5E4%7D+%5Cdelta%28%5Comega-q%5E%2B_1-q%5E%2B_2%29%7B%5Cbar+h%7D%28q_1%29+%5CPhi%28q_2%29++%5CPhi%5E%5Cdagger+%28q_3%29+h%28q_4%29++&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='= &#92;int &#92;mathrm{d}&#92;omega e^{&#92;frac{-i}{2}&#92;omega z^-}  &#92;int &#92;prod_{i=1}^{4} &#92;frac{&#92;mathrm{d}^4q_i}{(2&#92;pi)^4} &#92;delta(&#92;omega-q^+_1-q^+_2){&#92;bar h}(q_1) &#92;Phi(q_2)  &#92;Phi^&#92;dagger (q_3) h(q_4)  ' title='= &#92;int &#92;mathrm{d}&#92;omega e^{&#92;frac{-i}{2}&#92;omega z^-}  &#92;int &#92;prod_{i=1}^{4} &#92;frac{&#92;mathrm{d}^4q_i}{(2&#92;pi)^4} &#92;delta(&#92;omega-q^+_1-q^+_2){&#92;bar h}(q_1) &#92;Phi(q_2)  &#92;Phi^&#92;dagger (q_3) h(q_4)  ' class='latex' /> </p>
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		<title>note on renormalization</title>
		<link>http://tally.wordpress.com/2010/10/08/note-on-renormalization/</link>
		<comments>http://tally.wordpress.com/2010/10/08/note-on-renormalization/#comments</comments>
		<pubDate>Fri, 08 Oct 2010 06:09:25 +0000</pubDate>
		<dc:creator>xil41</dc:creator>
				<category><![CDATA[notes]]></category>

		<guid isPermaLink="false">http://tally.wordpress.com/?p=34</guid>
		<description><![CDATA[work in the scheme with dimension regularization . First every operator with fields of type could be written as . Thus, generally the correction to the operator will be of the form. . The ultra-violet term should be canceled by the counter-term, in this way could be determined order by order as long as we [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=tally.wordpress.com&amp;blog=376204&amp;post=34&amp;subd=tally&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>work in the <img src='http://s0.wp.com/latex.php?latex=%5Cbar%7B%5Crm%7BMS%7D%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;bar{&#92;rm{MS}}' title='&#92;bar{&#92;rm{MS}}' class='latex' /> scheme with dimension regularization <img src='http://s0.wp.com/latex.php?latex=d%3D4-2%5Cepsilon&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='d=4-2&#92;epsilon' title='d=4-2&#92;epsilon' class='latex' />.<br />
First every operator with <img src='http://s0.wp.com/latex.php?latex=n_i&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n_i' title='n_i' class='latex' /> fields of type <img src='http://s0.wp.com/latex.php?latex=i&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='i' title='i' class='latex' /> could be written as </p>
<p><img src='http://s0.wp.com/latex.php?latex=%7B%5Ccal+O%7D_R+%3D+%5Cprod_%7Bi%7D+Z_i%5E%7B%5Cfrac%7Bn_i%7D%7B2%7D%7D+Z%5E%7B-1%7D_%7B%5Ccal+O%7D+%5CGamma+%5CPhi_%7BR%2Ci%7D%5E%7Bn_i%7D+&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='{&#92;cal O}_R = &#92;prod_{i} Z_i^{&#92;frac{n_i}{2}} Z^{-1}_{&#92;cal O} &#92;Gamma &#92;Phi_{R,i}^{n_i} ' title='{&#92;cal O}_R = &#92;prod_{i} Z_i^{&#92;frac{n_i}{2}} Z^{-1}_{&#92;cal O} &#92;Gamma &#92;Phi_{R,i}^{n_i} ' class='latex' />.</p>
<p>Thus, generally the correction to the operator will be of the form.</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7BA_1%7D%7B%5Cbar%7B%5Cepsilon%7D%5E2_%7B%5Crm+UV%7D%7D+%2B+%5Cfrac%7BA_2%7D%7B%5Cbar%7B%5Cepsilon%7D_%7B%5Crm+UV%7D%7D++%2B+%5Cfrac%7BB_1%7D%7B%5Cbar%7B%5Cepsilon%7D%5E2_%7B%5Crm+IR%7D%7D+%2B+%5Cfrac%7BB_2%7D%7B%5Cbar%7B%5Cepsilon%7D_%7B%5Crm+IR%7D%7D++%2B+%7B%5Crm+finit+%5C+terms%7D+%2B+%5Csum_i+%5Cfrac%7Bn_i%7D%7B2%7D%5Cdelta+Z_i++-+%5Cdelta+Z_%7B%5Ccal+O%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;frac{A_1}{&#92;bar{&#92;epsilon}^2_{&#92;rm UV}} + &#92;frac{A_2}{&#92;bar{&#92;epsilon}_{&#92;rm UV}}  + &#92;frac{B_1}{&#92;bar{&#92;epsilon}^2_{&#92;rm IR}} + &#92;frac{B_2}{&#92;bar{&#92;epsilon}_{&#92;rm IR}}  + {&#92;rm finit &#92; terms} + &#92;sum_i &#92;frac{n_i}{2}&#92;delta Z_i  - &#92;delta Z_{&#92;cal O}' title='&#92;frac{A_1}{&#92;bar{&#92;epsilon}^2_{&#92;rm UV}} + &#92;frac{A_2}{&#92;bar{&#92;epsilon}_{&#92;rm UV}}  + &#92;frac{B_1}{&#92;bar{&#92;epsilon}^2_{&#92;rm IR}} + &#92;frac{B_2}{&#92;bar{&#92;epsilon}_{&#92;rm IR}}  + {&#92;rm finit &#92; terms} + &#92;sum_i &#92;frac{n_i}{2}&#92;delta Z_i  - &#92;delta Z_{&#92;cal O}' class='latex' />.</p>
<p>The ultra-violet term should be canceled by the counter-term, in this way <img src='http://s0.wp.com/latex.php?latex=Z_%7B%5Ccal+O%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='Z_{&#92;cal O}' title='Z_{&#92;cal O}' class='latex' /> could be determined order by order as long as we know <img src='http://s0.wp.com/latex.php?latex=Z_%7Bi%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='Z_{i}' title='Z_{i}' class='latex' />.</p>
<p>Secondly, since <img src='http://s0.wp.com/latex.php?latex=%7B%5Ccal+O%7D_0+%3D+Z_%7B%5Ccal+O%7D+%7B%5Ccal+O%7D_R&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='{&#92;cal O}_0 = Z_{&#92;cal O} {&#92;cal O}_R' title='{&#92;cal O}_0 = Z_{&#92;cal O} {&#92;cal O}_R' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%7B%5Ccal+O%7D_0&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='{&#92;cal O}_0' title='{&#92;cal O}_0' class='latex' /> is scale<br />
independent. Thus <img src='http://s0.wp.com/latex.php?latex=%5Cmu+%5Cmathrm%7Bd%7D+%28+Z_%7B%5Ccal+O%7D+%7B%5Ccal+O%7D_R+%29%2F+%5Cmathrm%7Bd%7D+%5Cmu++%3D+0+&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;mu &#92;mathrm{d} ( Z_{&#92;cal O} {&#92;cal O}_R )/ &#92;mathrm{d} &#92;mu  = 0 ' title='&#92;mu &#92;mathrm{d} ( Z_{&#92;cal O} {&#92;cal O}_R )/ &#92;mathrm{d} &#92;mu  = 0 ' class='latex' />. </p>
<p>Third, the correction to the propagator is denoted as <img src='http://s0.wp.com/latex.php?latex=-i%5CSigma&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='-i&#92;Sigma' title='-i&#92;Sigma' class='latex' />, thus the full propagator is <img src='http://s0.wp.com/latex.php?latex=i%2F%28%7B%5Cbar+p%7D+-m+-%5CSigma%5Bp%5D%29+%3D+iR%2F%28%7B%5Cbar+p%7D+-+m%29+%2B%7B%5Crm+analytic+%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='i/({&#92;bar p} -m -&#92;Sigma[p]) = iR/({&#92;bar p} - m) +{&#92;rm analytic }' title='i/({&#92;bar p} -m -&#92;Sigma[p]) = iR/({&#92;bar p} - m) +{&#92;rm analytic }' class='latex' />. Once on shell, only the residual part will survive due to the LSZ reduction formula and give a contribution <img src='http://s0.wp.com/latex.php?latex=%5Csqrt%7BR%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;sqrt{R}' title='&#92;sqrt{R}' class='latex' />.<br />
The fermion self energy has the form </p>
<p><img src='http://s0.wp.com/latex.php?latex=%5CSigma_i%5Bp%5D+%3D+%28A_i%5Bp%5E2%5D%2BB_i%5Bp%5E2%5D%29+m_i+%2B+B_i%5Bp%5E2%5D+%28%7B%5Cbar+p%7D+-+m_i%29&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;Sigma_i[p] = (A_i[p^2]+B_i[p^2]) m_i + B_i[p^2] ({&#92;bar p} - m_i)' title='&#92;Sigma_i[p] = (A_i[p^2]+B_i[p^2]) m_i + B_i[p^2] ({&#92;bar p} - m_i)' class='latex' />.</p>
<p>and its counter term</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5CSigma_%7Bct%7D+%3D+-%5Cdelta+Z_i%28%7B%5Cbar+p%7D+-+m_i%29+%2B+%5Cdelta+Z_m+m_i+&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;Sigma_{ct} = -&#92;delta Z_i({&#92;bar p} - m_i) + &#92;delta Z_m m_i ' title='&#92;Sigma_{ct} = -&#92;delta Z_i({&#92;bar p} - m_i) + &#92;delta Z_m m_i ' class='latex' />.</p>
<p>Therefore the contribution to <img src='http://s0.wp.com/latex.php?latex=R&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='R' title='R' class='latex' /> is given by </p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdelta+R_i+%3D+B_i%5Bm_i%5E2%5D+%2B+2m_i%5E2+%5Cfrac%7B%5Cmathrm%7Bd%7D%28A_i%2BB_i%29%7D%7B%5Cmathrm%7Bd%7Dp%5E2%7D%7C_%7Bp%5E2%3Dm_i%5E2%7D+-%5Cdelta+Z_i&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;delta R_i = B_i[m_i^2] + 2m_i^2 &#92;frac{&#92;mathrm{d}(A_i+B_i)}{&#92;mathrm{d}p^2}|_{p^2=m_i^2} -&#92;delta Z_i' title='&#92;delta R_i = B_i[m_i^2] + 2m_i^2 &#92;frac{&#92;mathrm{d}(A_i+B_i)}{&#92;mathrm{d}p^2}|_{p^2=m_i^2} -&#92;delta Z_i' class='latex' />.</p>
<p>Last, in effective theory in some cases the integrations involved will be scaleless, thus zero. Hence the operator with <img src='http://s0.wp.com/latex.php?latex=n_j&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n_j' title='n_j' class='latex' /> external legs of type <img src='http://s0.wp.com/latex.php?latex=j&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='j' title='j' class='latex' /> will have corrections (all infrared divergence):</p>
<p><img src='http://s0.wp.com/latex.php?latex=-+%5Csum_j+%5Cfrac%7Bn_j%7D%7B2%7D%5Cdelta+Z_j+%2B+%5Csum_i+%5Cfrac%7Bn_i%7D%7B2%7D%5Cdelta+Z_i++-+%5Cdelta+Z_%7B%5Ccal+O%7D%3D++-+%5Csum_j+%5Cfrac%7Bn_j%7D%7B2%7D%5Cdelta+Z_j+-+%5Cfrac%7BA_1%7D%7B%5Cbar%7B%5Cepsilon%7D%5E2%7D+-%5Cfrac%7BA_2%7D%7B%5Cbar%7B%5Cepsilon%7D%7D+&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='- &#92;sum_j &#92;frac{n_j}{2}&#92;delta Z_j + &#92;sum_i &#92;frac{n_i}{2}&#92;delta Z_i  - &#92;delta Z_{&#92;cal O}=  - &#92;sum_j &#92;frac{n_j}{2}&#92;delta Z_j - &#92;frac{A_1}{&#92;bar{&#92;epsilon}^2} -&#92;frac{A_2}{&#92;bar{&#92;epsilon}} ' title='- &#92;sum_j &#92;frac{n_j}{2}&#92;delta Z_j + &#92;sum_i &#92;frac{n_i}{2}&#92;delta Z_i  - &#92;delta Z_{&#92;cal O}=  - &#92;sum_j &#92;frac{n_j}{2}&#92;delta Z_j - &#92;frac{A_1}{&#92;bar{&#92;epsilon}^2} -&#92;frac{A_2}{&#92;bar{&#92;epsilon}} ' class='latex' /> .</p>
<p>This should reproduce the IR poles in the full theory. </p>
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		<title>记录一下</title>
		<link>http://tally.wordpress.com/2009/07/10/%e8%ae%b0%e5%bd%95%e4%b8%80%e4%b8%8b/</link>
		<comments>http://tally.wordpress.com/2009/07/10/%e8%ae%b0%e5%bd%95%e4%b8%80%e4%b8%8b/#comments</comments>
		<pubDate>Fri, 10 Jul 2009 16:52:54 +0000</pubDate>
		<dc:creator>xil41</dc:creator>
				<category><![CDATA[about pc]]></category>

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		<description><![CDATA[有时候，因为不小心或烦，删除了有用的或还要用的文件，而且又清空了回收站（或直接删除而根本不放入回收站）。怎么办？别着急，只要你的电脑还没有运行磁盘整理，且系统完好，任何时候的文件都可以找回来。方法很简单：  1、单击“开始/运行”，输入regedit 打开注册表  2、依次展开： HKEY_LOCAL_MACHIME/SOFTWARE/microsoft /WINDOWS/CURRENTVERSION/EXPLORER/DESKTOP/NemeSpace 在左边空白处点击“新建”，选择“主键”，命名为“645FFO40—5081—101B—9F08—00AA002F954E”，再把右边的“默认”主键的键值设为“回收站”，退出注册表。  3、重启电脑即可见到被你删除的文件。<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=tally.wordpress.com&amp;blog=376204&amp;post=25&amp;subd=tally&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>有时候，因为不小心或烦，删除了有用的或还要用的文件，而且又清空了回收站（或直接删除而根本不放入回收站）。怎么办？别着急，只要你的电脑还没有运行磁盘整理，且系统完好，任何时候的文件都可以找回来。方法很简单： <br style="margin:0;padding:0;" /> 1、单击“开始/运行”，输入regedit 打开注册表 <br style="margin:0;padding:0;" /><br style="margin:0;padding:0;" /> 2、依次展开：</p>
<p>HKEY_LOCAL_MACHIME/SOFTWARE/microsoft</p>
<p>/WINDOWS/CURRENTVERSION/EXPLORER/DESKTOP/NemeSpace</p>
<p>在左边空白处点击“新建”，选择“主键”，命名为“645FFO40—5081—101B—9F08—00AA002F954E”，再把右边的“默认”主键的键值设为“回收站”，退出注册表。 <br style="margin:0;padding:0;" /><br style="margin:0;padding:0;" /> 3、重启电脑即可见到被你删除的文件。</p>
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		<title>notes on quantization of Gauge field II — De Witt–Faddeev–Popov Approach</title>
		<link>http://tally.wordpress.com/2007/01/09/notes-on-quantization-of-gauge-field-ii-%e2%80%94-de-witt%e2%80%93faddeev%e2%80%93popov-approach/</link>
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		<pubDate>Tue, 09 Jan 2007 03:44:37 +0000</pubDate>
		<dc:creator>xil41</dc:creator>
				<category><![CDATA[notes]]></category>

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		<description><![CDATA[There is a good reason to use De Witt–Faddeev–Popov approach in practice to quantize the gauge field. It&#8217;s easy. Compare with using Dirac brackets, this functional approach is much easier to get the Feynman rules, especially for non-Abelian case. Consider partition function . Here I is the gauge invariant action: . And also the measure [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=tally.wordpress.com&amp;blog=376204&amp;post=23&amp;subd=tally&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>There is a good reason to use De Witt–Faddeev–Popov approach in practice to quantize the gauge field. It&#8217;s easy. Compare with using Dirac brackets, this functional approach is much easier to get the Feynman rules, especially for non-Abelian case.</p>
<p>Consider partition function</p>
<p><img src='http://s0.wp.com/latex.php?latex=Z+%3D+%5Cint+D+A%5E%5Calpha_%5Cmu++D+%5Cpsi%5E%7B%5Calpha%5Cdagger%7D+D+%5Cpsi%5E%5Calpha+exp%28iI%5BA%2C%5Cpsi%2C%5Cpsi%5E%5Cdagger%5D%29&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='Z = &#92;int D A^&#92;alpha_&#92;mu  D &#92;psi^{&#92;alpha&#92;dagger} D &#92;psi^&#92;alpha exp(iI[A,&#92;psi,&#92;psi^&#92;dagger])' title='Z = &#92;int D A^&#92;alpha_&#92;mu  D &#92;psi^{&#92;alpha&#92;dagger} D &#92;psi^&#92;alpha exp(iI[A,&#92;psi,&#92;psi^&#92;dagger])' class='latex' />.</p>
<p>Here I is the gauge invariant action: <img src='http://s0.wp.com/latex.php?latex=I%5BA%2C%5Cpsi%2C%5Cpsi%5E%5Cdagger%5D+%3D+I%5B%7B%7D%5E%5COmega+A%2C%7B%7D%5E%5COmega+%5Cpsi%2C%7B%7D%5E%5COmega+%5Cpsi%5E%5Cdagger%5D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='I[A,&#92;psi,&#92;psi^&#92;dagger] = I[{}^&#92;Omega A,{}^&#92;Omega &#92;psi,{}^&#92;Omega &#92;psi^&#92;dagger]' title='I[A,&#92;psi,&#92;psi^&#92;dagger] = I[{}^&#92;Omega A,{}^&#92;Omega &#92;psi,{}^&#92;Omega &#92;psi^&#92;dagger]' class='latex' />. And also the measure is assumed to be gauge invariant say, <img src='http://s0.wp.com/latex.php?latex=D+A%5E%5Calpha_%5Cmu++D+%5Cpsi%5E%7B%5Calpha%5Cdagger%7D+D+%5Cpsi%5E%5Calpha+%3D+D+%7B%7D%5E%5COmega+A%5E%5Calpha_%5Cmu++D+%7B%7D%5E%5COmega+%5Cpsi%5E%7B%5Calpha%5Cdagger%7D+D+%7B%7D%5E%5COmega+%5Cpsi%5E%5Calpha&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='D A^&#92;alpha_&#92;mu  D &#92;psi^{&#92;alpha&#92;dagger} D &#92;psi^&#92;alpha = D {}^&#92;Omega A^&#92;alpha_&#92;mu  D {}^&#92;Omega &#92;psi^{&#92;alpha&#92;dagger} D {}^&#92;Omega &#92;psi^&#92;alpha' title='D A^&#92;alpha_&#92;mu  D &#92;psi^{&#92;alpha&#92;dagger} D &#92;psi^&#92;alpha = D {}^&#92;Omega A^&#92;alpha_&#92;mu  D {}^&#92;Omega &#92;psi^{&#92;alpha&#92;dagger} D {}^&#92;Omega &#92;psi^&#92;alpha' class='latex' />.However, in the gauge field case, <img src='http://s0.wp.com/latex.php?latex=Z&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='Z' title='Z' class='latex' /> will not be convergent, for all those fields can be different by a gauge, and leave the physical results unchanged. In this way, the integral will count the same value over and over again hence making <img src='http://s0.wp.com/latex.php?latex=Z&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='Z' title='Z' class='latex' /> diverge. So intuitively, we should expect that <img src='http://s0.wp.com/latex.php?latex=Z+%3D+N+%5Ccdot+z&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='Z = N &#92;cdot z' title='Z = N &#92;cdot z' class='latex' />, where <img src='http://s0.wp.com/latex.php?latex=z&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='z' title='z' class='latex' /> is the value of the integral for one gauge choice, and N is the number of possible gauges which is of course infinity. If we can write <img src='http://s0.wp.com/latex.php?latex=Z&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='Z' title='Z' class='latex' />  as <img src='http://s0.wp.com/latex.php?latex=Z+%3D+N+%5Ccdot+z&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='Z = N &#92;cdot z' title='Z = N &#92;cdot z' class='latex' />, we can just strip off the unimportant overall factor <img src='http://s0.wp.com/latex.php?latex=N&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='N' title='N' class='latex' /> and only take care of the value of <img src='http://s0.wp.com/latex.php?latex=z&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='z' title='z' class='latex' /> to calculate physical interesting stuffs.</p>
<p>The way to realize this is to insert some <img src='http://s0.wp.com/latex.php?latex=%5Cdelta&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;delta' title='&#92;delta' class='latex' /> function to fix the gauge. For example if we use the Lorentz gauge, we&#8217;d better be able to insert something like <img src='http://s0.wp.com/latex.php?latex=%5Cdelta%28%5Cpartial%5E%5Cmu+A%5E%5Calpha_%5Cmu+-+%5Clambda%29&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;delta(&#92;partial^&#92;mu A^&#92;alpha_&#92;mu - &#92;lambda)' title='&#92;delta(&#92;partial^&#92;mu A^&#92;alpha_&#92;mu - &#92;lambda)' class='latex' /> and not change the value of <img src='http://s0.wp.com/latex.php?latex=Z&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='Z' title='Z' class='latex' />.</p>
<p>To proceed, we refresh our mind by reviewing a character for <img src='http://s0.wp.com/latex.php?latex=%5Cdelta&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;delta' title='&#92;delta' class='latex' />-function:</p>
<p><img src='http://s0.wp.com/latex.php?latex=%5Cdelta%28f%28x%29-f%28a%29%29+%3D+%5Cdelta%28x-a%29%2FDet%7Cf%27%28a%29%7C&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;delta(f(x)-f(a)) = &#92;delta(x-a)/Det|f&#039;(a)|' title='&#92;delta(f(x)-f(a)) = &#92;delta(x-a)/Det|f&#039;(a)|' class='latex' />,</p>
<p>which leads to <img src='http://s0.wp.com/latex.php?latex=Det%7Cf%27%28a%29%7C+%5Cdelta%28f%28x%29-f%28a%29%29%3D+%5Cdelta%28x-a%29&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='Det|f&#039;(a)| &#92;delta(f(x)-f(a))= &#92;delta(x-a)' title='Det|f&#039;(a)| &#92;delta(f(x)-f(a))= &#92;delta(x-a)' class='latex' />.And the determinant <img src='http://s0.wp.com/latex.php?latex=Det%7Cf%27%28a%29%7C&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='Det|f&#039;(a)|' title='Det|f&#039;(a)|' class='latex' /> is independent of <img src='http://s0.wp.com/latex.php?latex=x&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='x' title='x' class='latex' />.</p>
<p>Here we will encounter almost the same case, except for replacing <img src='http://s0.wp.com/latex.php?latex=x&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='x' title='x' class='latex' /> by some functional. We are about to insert in <img src='http://s0.wp.com/latex.php?latex=Z&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='Z' title='Z' class='latex' /> a constant <img src='http://s0.wp.com/latex.php?latex=%5Cint+D+%5COmega+Det%7C%5CDelta%7C+%5Cdelta%28f%28%5COmega%2C+x%29-%5Clambda%29+%3D+1&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;int D &#92;Omega Det|&#92;Delta| &#92;delta(f(&#92;Omega, x)-&#92;lambda) = 1' title='&#92;int D &#92;Omega Det|&#92;Delta| &#92;delta(f(&#92;Omega, x)-&#92;lambda) = 1' class='latex' />, where the <img src='http://s0.wp.com/latex.php?latex=f%28%5COmega%2Cx%29&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='f(&#92;Omega,x)' title='f(&#92;Omega,x)' class='latex' /> is some gauge choice. this obviously leaves <img src='http://s0.wp.com/latex.php?latex=Z&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='Z' title='Z' class='latex' /> unchanged. The integral was over all gauges <img src='http://s0.wp.com/latex.php?latex=%5COmega&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;Omega' title='&#92;Omega' class='latex' />. Here , <img src='http://s0.wp.com/latex.php?latex=Det%7C%5CDelta%7C&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='Det|&#92;Delta|' title='Det|&#92;Delta|' class='latex' /> is called Faddeev–Popov determinant and it&#8217;s easy to show that it is independent of gauge choice <img src='http://s0.wp.com/latex.php?latex=%5COmega&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;Omega' title='&#92;Omega' class='latex' />.<br />
After doing so and noting those gauge independent elements, we get<br />
<img src='http://s0.wp.com/latex.php?latex=Z+%3D+%5Cint+D+A%5E%5Calpha_%5Cmu++D+%5Cpsi%5E%7B%5Calpha%5Cdagger%7D+D+%5Cpsi%5E%5Calpha+D+%5COmega+Det%7C%5CDelta%7C+%5Cdelta%28f%28%5COmega%2C+x%29-%5Clambda%29+++exp%28iI%5BA%2C%5Cpsi%2C%5Cpsi%5E%5Cdagger%5D%29&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='Z = &#92;int D A^&#92;alpha_&#92;mu  D &#92;psi^{&#92;alpha&#92;dagger} D &#92;psi^&#92;alpha D &#92;Omega Det|&#92;Delta| &#92;delta(f(&#92;Omega, x)-&#92;lambda)   exp(iI[A,&#92;psi,&#92;psi^&#92;dagger])' title='Z = &#92;int D A^&#92;alpha_&#92;mu  D &#92;psi^{&#92;alpha&#92;dagger} D &#92;psi^&#92;alpha D &#92;Omega Det|&#92;Delta| &#92;delta(f(&#92;Omega, x)-&#92;lambda)   exp(iI[A,&#92;psi,&#92;psi^&#92;dagger])' class='latex' />.</p>
<p><img src='http://s0.wp.com/latex.php?latex=%3D%5Cint+D+%5COmega+%5Cint+D+A%5E%5Calpha_%5Cmu++D+%5Cpsi%5E%7B%5Calpha%5Cdagger%7D+D+%5Cpsi%5E%5Calpha+Det%7C%5CDelta%7C+%5Cdelta%28f%28%5COmega_%7Bfix%7D%2C+x%29-%5Clambda%29+exp%28iI%5BA%2C%5Cpsi%2C%5Cpsi%5E%5Cdagger%5D%29&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='=&#92;int D &#92;Omega &#92;int D A^&#92;alpha_&#92;mu  D &#92;psi^{&#92;alpha&#92;dagger} D &#92;psi^&#92;alpha Det|&#92;Delta| &#92;delta(f(&#92;Omega_{fix}, x)-&#92;lambda) exp(iI[A,&#92;psi,&#92;psi^&#92;dagger])' title='=&#92;int D &#92;Omega &#92;int D A^&#92;alpha_&#92;mu  D &#92;psi^{&#92;alpha&#92;dagger} D &#92;psi^&#92;alpha Det|&#92;Delta| &#92;delta(f(&#92;Omega_{fix}, x)-&#92;lambda) exp(iI[A,&#92;psi,&#92;psi^&#92;dagger])' class='latex' /></p>
<p>Now we can drop  the overall factor <img src='http://s0.wp.com/latex.php?latex=%5Cint+D+%5COmega&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;int D &#92;Omega' title='&#92;int D &#92;Omega' class='latex' /> and if by indroducing a fermion like field (Faddeev–Popov ghost) making</p>
<p><img src='http://s0.wp.com/latex.php?latex=Det%7C%5CDelta%7C%3D+%5Cint+D+%5Comega%5E%5Cdagger+D+%5Comega++exp%28i+%5Comega%5E%5Cdagger+%5CDelta+%5Comega%29&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='Det|&#92;Delta|= &#92;int D &#92;omega^&#92;dagger D &#92;omega  exp(i &#92;omega^&#92;dagger &#92;Delta &#92;omega)' title='Det|&#92;Delta|= &#92;int D &#92;omega^&#92;dagger D &#92;omega  exp(i &#92;omega^&#92;dagger &#92;Delta &#92;omega)' class='latex' />,</p>
<p>we get</p>
<p><img src='http://s0.wp.com/latex.php?latex=Z+%3D+%5Cint+D+A%5E%5Calpha_%5Cmu++D+%5Cpsi%5E%7B%5Calpha%5Cdagger%7D+D+%5Cpsi%5E%5Calpha+D+%5Comega%5E%5Cdagger+D+%5Comega+%5Cdelta%28f%28%5COmega_%7Bfix%7D%2C+x%29-%5Clambda%29++exp%28iI%5BA%2C%5Cpsi%2C%5Cpsi%5E%5Cdagger%5D%2Bi+%5Comega%5E%5Cdagger+%5CDelta+%5Comega%29&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='Z = &#92;int D A^&#92;alpha_&#92;mu  D &#92;psi^{&#92;alpha&#92;dagger} D &#92;psi^&#92;alpha D &#92;omega^&#92;dagger D &#92;omega &#92;delta(f(&#92;Omega_{fix}, x)-&#92;lambda)  exp(iI[A,&#92;psi,&#92;psi^&#92;dagger]+i &#92;omega^&#92;dagger &#92;Delta &#92;omega)' title='Z = &#92;int D A^&#92;alpha_&#92;mu  D &#92;psi^{&#92;alpha&#92;dagger} D &#92;psi^&#92;alpha D &#92;omega^&#92;dagger D &#92;omega &#92;delta(f(&#92;Omega_{fix}, x)-&#92;lambda)  exp(iI[A,&#92;psi,&#92;psi^&#92;dagger]+i &#92;omega^&#92;dagger &#92;Delta &#92;omega)' class='latex' />.</p>
<p>Finally we multiply <img src='http://s0.wp.com/latex.php?latex=Z&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='Z' title='Z' class='latex' /> by some distribution function, usually guassian-type <img src='http://s0.wp.com/latex.php?latex=%5Cint+D%5Clambda+exp%28-+%5Cfrac%7Bi%7D%7B2%5Cxi%7D+%5Clambda%5E2%29&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;int D&#92;lambda exp(- &#92;frac{i}{2&#92;xi} &#92;lambda^2)' title='&#92;int D&#92;lambda exp(- &#92;frac{i}{2&#92;xi} &#92;lambda^2)' class='latex' />, and use the fact that <img src='http://s0.wp.com/latex.php?latex=Z&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='Z' title='Z' class='latex' /> doesn&#8217;t depend on <img src='http://s0.wp.com/latex.php?latex=%5Clambda&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;lambda' title='&#92;lambda' class='latex' />. So we can integrate out the <img src='http://s0.wp.com/latex.php?latex=%5Cdelta&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;delta' title='&#92;delta' class='latex' />-function and get<br />
<img src='http://s0.wp.com/latex.php?latex=Z+%3D+%5Cint+D+A%5E%5Calpha_%5Cmu++D+%5Cpsi%5E%7B%5Calpha%5Cdagger%7D+D+%5Cpsi%5E%5Calpha+D+%5Comega%5E%5Cdagger+D+%5Comega+exp%28iI%5BA%2C%5Cpsi%2C%5Cpsi%5E%5Cdagger%5D-i+%5Cfrac%7Bi%7D%7B2%5Cxi%7D+f%5E2%2B+i+%5Comega%5E%5Cdagger+%5CDelta+%5Comega%29&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='Z = &#92;int D A^&#92;alpha_&#92;mu  D &#92;psi^{&#92;alpha&#92;dagger} D &#92;psi^&#92;alpha D &#92;omega^&#92;dagger D &#92;omega exp(iI[A,&#92;psi,&#92;psi^&#92;dagger]-i &#92;frac{i}{2&#92;xi} f^2+ i &#92;omega^&#92;dagger &#92;Delta &#92;omega)' title='Z = &#92;int D A^&#92;alpha_&#92;mu  D &#92;psi^{&#92;alpha&#92;dagger} D &#92;psi^&#92;alpha D &#92;omega^&#92;dagger D &#92;omega exp(iI[A,&#92;psi,&#92;psi^&#92;dagger]-i &#92;frac{i}{2&#92;xi} f^2+ i &#92;omega^&#92;dagger &#92;Delta &#92;omega)' class='latex' /></p>
<p><img src='http://s0.wp.com/latex.php?latex=%3D+%5Cint+D+A%5E%5Calpha_%5Cmu++D+%5Cpsi%5E%7B%5Calpha%5Cdagger%7D+D+%5Cpsi%5E%5Calpha+D+%5Comega%5E%5Cdagger+D+%5Comega+exp%28iI_%7BNEW%7D+%5BA%2C%5Cpsi%2C%5Cpsi%5E%5Cdagger%2C+%5Comega%5E%5Cdagger%2C+%5Comega%5D%29.&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='= &#92;int D A^&#92;alpha_&#92;mu  D &#92;psi^{&#92;alpha&#92;dagger} D &#92;psi^&#92;alpha D &#92;omega^&#92;dagger D &#92;omega exp(iI_{NEW} [A,&#92;psi,&#92;psi^&#92;dagger, &#92;omega^&#92;dagger, &#92;omega]).' title='= &#92;int D A^&#92;alpha_&#92;mu  D &#92;psi^{&#92;alpha&#92;dagger} D &#92;psi^&#92;alpha D &#92;omega^&#92;dagger D &#92;omega exp(iI_{NEW} [A,&#92;psi,&#92;psi^&#92;dagger, &#92;omega^&#92;dagger, &#92;omega]).' class='latex' /><br />
Here <img src='http://s0.wp.com/latex.php?latex=I_%7BNEW%7D+%5BA%2C%5Cpsi%2C%5Cpsi%5E%5Cdagger%2C+%5Comega%5E%5Cdagger%2C+%5Comega%5D+%3D+I%5BA%2C%5Cpsi%2C%5Cpsi%5E%5Cdagger%5D-i+%5Cfrac%7Bi%7D%7B2%5Cxi%7D+f%5E2%2B+i+%5Comega%5E%5Cdagger+%5CDelta+%5Comega&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='I_{NEW} [A,&#92;psi,&#92;psi^&#92;dagger, &#92;omega^&#92;dagger, &#92;omega] = I[A,&#92;psi,&#92;psi^&#92;dagger]-i &#92;frac{i}{2&#92;xi} f^2+ i &#92;omega^&#92;dagger &#92;Delta &#92;omega' title='I_{NEW} [A,&#92;psi,&#92;psi^&#92;dagger, &#92;omega^&#92;dagger, &#92;omega] = I[A,&#92;psi,&#92;psi^&#92;dagger]-i &#92;frac{i}{2&#92;xi} f^2+ i &#92;omega^&#92;dagger &#92;Delta &#92;omega' class='latex' />. The second term is the gauge fixed term, the third the ghost field.</p>
<p>After all, we should note here that though we choose a gauge, this <img src='http://s0.wp.com/latex.php?latex=Z&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='Z' title='Z' class='latex' />  really does NOT care about what kind gauge we have chosen. That is to say after you evaluate a physical interesting thing such as cross section, the <img src='http://s0.wp.com/latex.php?latex=%5Cxi&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;xi' title='&#92;xi' class='latex' /> will be canceled out and shouldn&#8217;t show up in your final results(if it does, you make some mistakes).</p>
<p>Last we take the QCD as an example. We will use both Lorentz gauge(<img src='http://s0.wp.com/latex.php?latex=%5Cpartial%5E%5Cmu+A%5E%5Calpha_%5Cmu+%3D+0&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;partial^&#92;mu A^&#92;alpha_&#92;mu = 0' title='&#92;partial^&#92;mu A^&#92;alpha_&#92;mu = 0' class='latex' />) and axial gauge(<img src='http://s0.wp.com/latex.php?latex=A%5E%5Calpha_3+%3D+0&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='A^&#92;alpha_3 = 0' title='A^&#92;alpha_3 = 0' class='latex' />). In QCD, <img src='http://s0.wp.com/latex.php?latex=A%5E%5Calpha_%5Cmu&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='A^&#92;alpha_&#92;mu' title='A^&#92;alpha_&#92;mu' class='latex' /> transform as <img src='http://s0.wp.com/latex.php?latex=A%5E%5Calpha_%5Cmu+%5Crightarrow+A%5E%5Calpha_%5Cmu+%2B+D_%5Cmu+%5COmega%5E%5Calpha&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='A^&#92;alpha_&#92;mu &#92;rightarrow A^&#92;alpha_&#92;mu + D_&#92;mu &#92;Omega^&#92;alpha' title='A^&#92;alpha_&#92;mu &#92;rightarrow A^&#92;alpha_&#92;mu + D_&#92;mu &#92;Omega^&#92;alpha' class='latex' /> .</p>
<p>So for  Lorentz gauge <img src='http://s0.wp.com/latex.php?latex=f%5E%5Calpha+%3D%5Cpartial%5E%5Cmu+A%5E%5Calpha_%5Cmu&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='f^&#92;alpha =&#92;partial^&#92;mu A^&#92;alpha_&#92;mu' title='f^&#92;alpha =&#92;partial^&#92;mu A^&#92;alpha_&#92;mu' class='latex' />, <img src='http://s0.wp.com/latex.php?latex=%5CDelta+%3D+%5Cfrac%7B%5Cpartial+f%5E%5Calpha%7D%7B%5Cpartial+%5COmega%5E%5Cbeta%7D+%3D+%5Cdelta_%7B%5Calpha+%5Cbeta%7D+%5Cpartial%5E%5Cmu+D_%5Cmu&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;Delta = &#92;frac{&#92;partial f^&#92;alpha}{&#92;partial &#92;Omega^&#92;beta} = &#92;delta_{&#92;alpha &#92;beta} &#92;partial^&#92;mu D_&#92;mu' title='&#92;Delta = &#92;frac{&#92;partial f^&#92;alpha}{&#92;partial &#92;Omega^&#92;beta} = &#92;delta_{&#92;alpha &#92;beta} &#92;partial^&#92;mu D_&#92;mu' class='latex' />.</p>
<p>And for axial case, <img src='http://s0.wp.com/latex.php?latex=f%5E%5Calpha+%3DA%5E%5Calpha_3&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='f^&#92;alpha =A^&#92;alpha_3' title='f^&#92;alpha =A^&#92;alpha_3' class='latex' />, <img src='http://s0.wp.com/latex.php?latex=%5CDelta+%3D+%5Cfrac%7B%5Cpartial+f%5E%5Calpha%7D%7B%5Cpartial+%5COmega%5E%5Cbeta%7D++%3D+%5Cdelta_%7B%5Calpha+%5Cbeta%7D+%5Cpartial_3&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;Delta = &#92;frac{&#92;partial f^&#92;alpha}{&#92;partial &#92;Omega^&#92;beta}  = &#92;delta_{&#92;alpha &#92;beta} &#92;partial_3' title='&#92;Delta = &#92;frac{&#92;partial f^&#92;alpha}{&#92;partial &#92;Omega^&#92;beta}  = &#92;delta_{&#92;alpha &#92;beta} &#92;partial_3' class='latex' /> (remember that <img src='http://s0.wp.com/latex.php?latex=A%5E%5Calpha_3+%3D+0&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='A^&#92;alpha_3 = 0' title='A^&#92;alpha_3 = 0' class='latex' />). So in the axial case, we see that the ghosts decouple and by gauge indepence, they should decouple in general.</p>
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		<title>notes on quantization of Gauge field I &#8212; Dirac Bracket</title>
		<link>http://tally.wordpress.com/2007/01/04/note-on-quantization-of-gauge-field-i-dirac-bracket/</link>
		<comments>http://tally.wordpress.com/2007/01/04/note-on-quantization-of-gauge-field-i-dirac-bracket/#comments</comments>
		<pubDate>Thu, 04 Jan 2007 19:18:12 +0000</pubDate>
		<dc:creator>xil41</dc:creator>
				<category><![CDATA[notes]]></category>

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		<description><![CDATA[ Dirac bracket is an extension of Poisson bracket, used to deal with the Hamiltonian with constraints. Especially it is useful in quantizing gauge theories. In detail, Dirac bracket is defined as , where is the Poisson bracket, is some constraints such as a gauge condition, and is some matrix we will talk about later. Suppose [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=tally.wordpress.com&amp;blog=376204&amp;post=22&amp;subd=tally&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p> Dirac bracket is an extension of Poisson bracket, used to deal with the Hamiltonian with constraints. Especially it is useful in quantizing gauge theories. In detail, Dirac bracket is defined as <img src='http://s0.wp.com/latex.php?latex=%5BA%2CB%5D_D%3D+%5BA%2CB%5D_P+-+%5BA%2C+%5CPhi_i%5D_P+%28%5CDelta%5E%7B-1%7D%29%5E%7Bij%7D+%5B%5CPhi_j%2CB%5D_P&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='[A,B]_D= [A,B]_P - [A, &#92;Phi_i]_P (&#92;Delta^{-1})^{ij} [&#92;Phi_j,B]_P' title='[A,B]_D= [A,B]_P - [A, &#92;Phi_i]_P (&#92;Delta^{-1})^{ij} [&#92;Phi_j,B]_P' class='latex' />, where <img src='http://s0.wp.com/latex.php?latex=%5B%2C%5D_P&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='[,]_P' title='[,]_P' class='latex' /> is the Poisson bracket, <img src='http://s0.wp.com/latex.php?latex=%5CPhi&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;Phi' title='&#92;Phi' class='latex' /> is some constraints such as a gauge condition, and <img src='http://s0.wp.com/latex.php?latex=%5CDelta&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;Delta' title='&#92;Delta' class='latex' /> is some matrix we will talk about later.</p>
<p>Suppose there exits a Hamiltonian <img src='http://s0.wp.com/latex.php?latex=H&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='H' title='H' class='latex' /> with a set of constraints <img src='http://s0.wp.com/latex.php?latex=%5C%7B+%5CPhi_i+%5Capprox+0+%5C%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;{ &#92;Phi_i &#92;approx 0 &#92;}' title='&#92;{ &#92;Phi_i &#92;approx 0 &#92;}' class='latex' /> (Here &#8220;<img src='http://s0.wp.com/latex.php?latex=%5Capprox+&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;approx ' title='&#92;approx ' class='latex' />&#8221; means equations hold on shell, say after evaluate all the Poisson brackets then turn on the constraints conditions. We call this &#8220;weakly equal to&#8221;). For example, in E&amp;M theory, <img src='http://s0.wp.com/latex.php?latex=L+%3D+F%5E%7B%5Cmu+%5Cnu%7DF_%7B%5Cmu+%5Cnu%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='L = F^{&#92;mu &#92;nu}F_{&#92;mu &#92;nu}' title='L = F^{&#92;mu &#92;nu}F_{&#92;mu &#92;nu}' class='latex' />. So the canonical momenta are <img src='http://s0.wp.com/latex.php?latex=%5CPi%5E%5Cmu%3DF%5E%7B0%5Cmu%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;Pi^&#92;mu=F^{0&#92;mu}' title='&#92;Pi^&#92;mu=F^{0&#92;mu}' class='latex' />. We immediately get a set of <em>primary</em> constraints that <img src='http://s0.wp.com/latex.php?latex=%5CPi%5E0+%5Capprox+0&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;Pi^0 &#92;approx 0' title='&#92;Pi^0 &#92;approx 0' class='latex' />(we call this a set of constraints, because the equation holds on every point of space time). These constraints are needed to hold all the time, so <img src='http://s0.wp.com/latex.php?latex=%5B%5CPi%5E0%2CH%5D+%3D+0&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='[&#92;Pi^0,H] = 0' title='[&#92;Pi^0,H] = 0' class='latex' /> is demanded; hence a set of <em>secondary</em> constraints <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_i+%5CPi%5Ei+%5Capprox+0&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;partial_i &#92;Pi^i &#92;approx 0' title='&#92;partial_i &#92;Pi^i &#92;approx 0' class='latex' /> follows. There are no more constraints here, because <img src='http://s0.wp.com/latex.php?latex=%5B%5Cpartial_i+%5CPi_i%2CH%5D+%3D+0&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='[&#92;partial_i &#92;Pi_i,H] = 0' title='[&#92;partial_i &#92;Pi_i,H] = 0' class='latex' /> reduces to <img src='http://s0.wp.com/latex.php?latex=0+%3D+0&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='0 = 0' title='0 = 0' class='latex' />(trivial). If it&#8217;s a non-trivial equation, we keep on this process until we get a &#8220;<img src='http://s0.wp.com/latex.php?latex=0+%3D+0&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='0 = 0' title='0 = 0' class='latex' />&#8220;.</p>
<p>According to Dirac, we decompose those constraints into two classes: the <em>first-class</em> constraints and the <em>second-class</em> constraints. The first-class constraint means its Poison bracket with all the other constraints vanishes <img src='http://s0.wp.com/latex.php?latex=%5B%5CPhi_i%2C%5CPhi_j%5D_P+%5Capprox+0&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='[&#92;Phi_i,&#92;Phi_j]_P &#92;approx 0' title='[&#92;Phi_i,&#92;Phi_j]_P &#92;approx 0' class='latex' /> on the other hand, the second-class does not, which indicates that no linear combination <img src='http://s0.wp.com/latex.php?latex=%5Csum+c_i+%5B%5CPhi_i%2C%5CPhi_j%5D_P&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;sum c_i [&#92;Phi_i,&#92;Phi_j]_P' title='&#92;sum c_i [&#92;Phi_i,&#92;Phi_j]_P' class='latex' /> vanishes. As the E&amp;M example above, <img src='http://s0.wp.com/latex.php?latex=%5CPi%5E0&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;Pi^0' title='&#92;Pi^0' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_i+%5CPi%5Ei&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;partial_i &#92;Pi^i' title='&#92;partial_i &#92;Pi^i' class='latex' /> are first-class constraints.</p>
<p>In quantizing the gauge field, the primary first-class constraints(such as <img src='http://s0.wp.com/latex.php?latex=%5CPi%5E0+%5Capprox+0%29&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;Pi^0 &#92;approx 0)' title='&#92;Pi^0 &#92;approx 0)' class='latex' /> or maybe all the first-class constraints are harmless for they can be eliminated by a choice of gauge. So we took linear combination of constraints so that as many constraints can be put into first-class as possible then eliminate them by choosing gauge. After that, we left with a set of second-class constraints.</p>
<p>The existence of the second-class constraints indicates some degrees of freedom are not physically important. The naive idea to deal with them is just to &#8220;throw them away&#8221; and only keeping those degrees of freedom of physical importance. For example, suppose that we have constraints <img src='http://s0.wp.com/latex.php?latex=p_1+%5Capprox+0&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='p_1 &#92;approx 0' title='p_1 &#92;approx 0' class='latex' />, <img src='http://s0.wp.com/latex.php?latex=q_1+%5Capprox+0&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='q_1 &#92;approx 0' title='q_1 &#92;approx 0' class='latex' />, we can just take <img src='http://s0.wp.com/latex.php?latex=p_1&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='p_1' title='p_1' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=q_1&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='q_1' title='q_1' class='latex' /> as identically <img src='http://s0.wp.com/latex.php?latex=0+&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='0 ' title='0 ' class='latex' />. This is a simplest example. For generalization, Dirac proposed the following scheme:</p>
<p>Since for second-class constraints no linear combination <img src='http://s0.wp.com/latex.php?latex=%5Csum+c_i%5B%5CPhi_i%2C%5CPhi_j%5D_P&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;sum c_i[&#92;Phi_i,&#92;Phi_j]_P' title='&#92;sum c_i[&#92;Phi_i,&#92;Phi_j]_P' class='latex' /> vanishes, then <img src='http://s0.wp.com/latex.php?latex=Det%28%5CDelta%29+%5Cneq+0&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='Det(&#92;Delta) &#92;neq 0' title='Det(&#92;Delta) &#92;neq 0' class='latex' />, where <img src='http://s0.wp.com/latex.php?latex=%5CDelta_%7Bij%7D+%5Cequiv+%5B%5CPhi_i%2C%5CPhi_j%5D_P&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;Delta_{ij} &#92;equiv [&#92;Phi_i,&#92;Phi_j]_P' title='&#92;Delta_{ij} &#92;equiv [&#92;Phi_i,&#92;Phi_j]_P' class='latex' />. Hence <img src='http://s0.wp.com/latex.php?latex=%5CDelta&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;Delta' title='&#92;Delta' class='latex' /> is reversible. By introducing Dirac bracket <img src='http://s0.wp.com/latex.php?latex=%5BA%2CB%5D_D+%3D+%5BA%2CB%5D_P+-+%5BA%2C%5CPhi_i%5D_P+%28%5CDelta%5E%7B-1%7D%29%5E%7Bij%7D%5B%5CPhi_j%2CB%5D_P&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='[A,B]_D = [A,B]_P - [A,&#92;Phi_i]_P (&#92;Delta^{-1})^{ij}[&#92;Phi_j,B]_P' title='[A,B]_D = [A,B]_P - [A,&#92;Phi_i]_P (&#92;Delta^{-1})^{ij}[&#92;Phi_j,B]_P' class='latex' />, we can get all commutation relations for canonical variables. And use them to quantize gauge field theory. We can check by using the <img src='http://s0.wp.com/latex.php?latex=p_1+%5Capprox+0&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='p_1 &#92;approx 0' title='p_1 &#92;approx 0' class='latex' />, <img src='http://s0.wp.com/latex.php?latex=q_1+%5Capprox+0&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='q_1 &#92;approx 0' title='q_1 &#92;approx 0' class='latex' />, that this scheme is the same as we throw away <img src='http://s0.wp.com/latex.php?latex=p_1&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='p_1' title='p_1' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=q_1&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='q_1' title='q_1' class='latex' />.</p>
<p>Still use the E&amp;M case as an example. First as we mentioned above , <img src='http://s0.wp.com/latex.php?latex=%5CPi%5E0+%3D+0&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;Pi^0 = 0' title='&#92;Pi^0 = 0' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_i+%5CPi%5Ei+%3D+0&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;partial_i &#92;Pi^i = 0' title='&#92;partial_i &#92;Pi^i = 0' class='latex' /> are first class constraints. Now we propose a gauge(here we use coulomb gauge) <img src='http://s0.wp.com/latex.php?latex=%5Cpartial%5Ei+A_i+%3D+0&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;partial^i A_i = 0' title='&#92;partial^i A_i = 0' class='latex' /> . Together with <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_i+%5CPi%5Ei%3D%5Cpartial_i+F%5E%7Bi0%7D+%3D+0&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;partial_i &#92;Pi^i=&#92;partial_i F^{i0} = 0' title='&#92;partial_i &#92;Pi^i=&#92;partial_i F^{i0} = 0' class='latex' />, we can eliminate <img src='http://s0.wp.com/latex.php?latex=A%5E0&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='A^0' title='A^0' class='latex' />(In this case <img src='http://s0.wp.com/latex.php?latex=A%5E0%3D+0&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='A^0= 0' title='A^0= 0' class='latex' />). Then we left with two second-class constraints: <img src='http://s0.wp.com/latex.php?latex=%5Cpartial_i+%5CPi%5Ei+%3D+0&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;partial_i &#92;Pi^i = 0' title='&#92;partial_i &#92;Pi^i = 0' class='latex' /> and the gauge condition <img src='http://s0.wp.com/latex.php?latex=%5Cpartial%5Ei+A_i+%3D+0&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;partial^i A_i = 0' title='&#92;partial^i A_i = 0' class='latex' />, since <img src='http://s0.wp.com/latex.php?latex=%5CDelta%5E%7B1+%5Cbold%7Bx%7D%2C2+%5Cbold%7By%7D%7D+%3D+-%5CDelta%5E%7B2+%5Cbold%7By%7D%2C1+%5Cbold%7Bx%7D%7D+%3D+%5B%5Cpartial%5Ei+A_i%2C+%5Cpartial_i+%5CPi%5Ei%5D_P+%3D++%5Cnabla%5E2+%5Cdelta%28+%5Cbold%7Bx%7D-%5Cbold%7By%7D%29&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;Delta^{1 &#92;bold{x},2 &#92;bold{y}} = -&#92;Delta^{2 &#92;bold{y},1 &#92;bold{x}} = [&#92;partial^i A_i, &#92;partial_i &#92;Pi^i]_P =  &#92;nabla^2 &#92;delta( &#92;bold{x}-&#92;bold{y})' title='&#92;Delta^{1 &#92;bold{x},2 &#92;bold{y}} = -&#92;Delta^{2 &#92;bold{y},1 &#92;bold{x}} = [&#92;partial^i A_i, &#92;partial_i &#92;Pi^i]_P =  &#92;nabla^2 &#92;delta( &#92;bold{x}-&#92;bold{y})' class='latex' />, Δ<sup>1<strong>x</strong>,1<strong>y</strong></sup>=Δ<sup>2<strong>x</strong>,2<strong>y</strong></sup> = 0, Det(Δ)≠0. Finally, we use the Dirac bracket we get, [A<sub>i</sub>, Π<sup>j</sup>]<sub>D</sub>= iδ<sup>i</sup><sub>j</sub>δ(<strong>x</strong>-<strong>y</strong>)+i ∂<sup>2</sup>/∂<sub>i</sub>∂<sub>j</sub>(1/4π|<strong>x</strong>-<strong>y</strong>|). And extend this to quantum version, to quantize E&amp;M.</p>
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		<title>Something New</title>
		<link>http://tally.wordpress.com/2006/12/25/next-project/</link>
		<comments>http://tally.wordpress.com/2006/12/25/next-project/#comments</comments>
		<pubDate>Mon, 25 Dec 2006 04:12:03 +0000</pubDate>
		<dc:creator>xil41</dc:creator>
				<category><![CDATA[notes]]></category>

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		<description><![CDATA[下一个project和这篇文章有关. 也是关于J/psi.  早就该看的, 不过碰上期末和假期, 一直压着. 和前一个pro不同, 这里涉及的scale仿佛多了一点. 先在这里标记一下.<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=tally.wordpress.com&amp;blog=376204&amp;post=21&amp;subd=tally&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>下一个project和<a title="p+gamma-&gt;j/psi" href="http://arxiv.org/abs/hep-ph/0607121" target="_blank">这篇文章</a>有关. 也是关于J/psi.  早就该看的, 不过碰上期末和假期, 一直压着. 和前一个pro不同, 这里涉及的scale仿佛多了一点. 先在这里标记一下.</p>
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		<title>Weinberg&#8217;s QFT</title>
		<link>http://tally.wordpress.com/2006/12/19/weinbergs-qft/</link>
		<comments>http://tally.wordpress.com/2006/12/19/weinbergs-qft/#comments</comments>
		<pubDate>Tue, 19 Dec 2006 06:53:32 +0000</pubDate>
		<dc:creator>xil41</dc:creator>
				<category><![CDATA[notes]]></category>

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		<description><![CDATA[很久没有看书(书终归是书, 还是和文献不同). 现在正好是学期末&#8211;无心向学但又不该休假， 晃荡了一周, 从疯狂的期末恢复过来, 想选本书看看了. 其实也没有选择余地, 手头没什么书, 随手抄了Weinberg的量子场论, 卷二. 以前大略看过卷一, 断断续续地读了几次, 但终没有看完. 坚持最长的是在完成peskin后, 认真读了卷一的前几章, 写的的确精彩. 印象深的是他在用群论(group theory: little group and etc.)来处理粒子场:不同粒子是洛仑兹群不同表示; 零质量粒子必定只有两个自旋分量等等. 这些是别的许多场论书,包括peskin, 都不曾谈及的. 所以如果说别的场论是&#8221;高等数学&#8221;的话, Weinberg的大概算是&#8221;数分&#8221;了. 除了书中用了一些拓扑, 群论的知识外, Weinberg的场论中的推导不是一般的跳, 也许是他不被推荐给入门者的理由之一了. 今天随便看了卷二的第一章, 也颇有收获. 他对BRST symmetry的论述相当精彩. 不过, 个人不喜欢他前面的Witt-Faddeev-Popov (non-Abelian)的介绍, 完全留于数学的推导. 但这也许因为在卷一中已有精彩介绍(E&#38;M Abelian case), 第九章, 只是我没有看过:D. 最后, 书是寝室长毕业前赠, 科大de盗版, 需阎xx签条子才能买, 很不错, 我喜欢.<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=tally.wordpress.com&amp;blog=376204&amp;post=18&amp;subd=tally&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>很久没有看书(书终归是书, 还是和文献不同).  现在正好是学期末&#8211;无心向学但又不该休假， 晃荡了一周, 从疯狂的期末恢复过来, 想选本书看看了.</p>
<p>其实也没有选择余地, 手头没什么书, 随手抄了Weinberg的量子场论, 卷二. 以前大略看过卷一, 断断续续地读了几次, 但终没有看完. 坚持最长的是在完成peskin后, 认真读了卷一的前几章, 写的的确精彩.  印象深的是他在用群论(group theory: little group and etc.)来处理粒子场:不同粒子是洛仑兹群不同表示; 零质量粒子必定只有两个自旋分量等等. 这些是别的许多场论书,包括peskin, 都不曾谈及的. 所以如果说别的场论是&#8221;高等数学&#8221;的话, Weinberg的大概算是&#8221;数分&#8221;了.  除了书中用了一些拓扑, 群论的知识外, Weinberg的场论中的推导不是一般的跳, 也许是他不被推荐给入门者的理由之一了.</p>
<p>今天随便看了卷二的第一章, 也颇有收获. 他对BRST symmetry的论述相当精彩. 不过, 个人不喜欢他前面的Witt-Faddeev-Popov (non-Abelian)的介绍, 完全留于数学的推导. 但这也许因为在卷一中已有精彩介绍(E&amp;M Abelian case), 第九章, 只是我没有看过:D.</p>
<p>最后, 书是寝室长毕业前赠, 科大de盗版, 需阎xx签条子才能买, 很不错, 我喜欢.</p>
<p><img src="http://tally.files.wordpress.com/2006/12/weinberg1.jpg?w=450" alt="weinberg1.jpg" /></p>
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		<slash:comments>1</slash:comments>
	
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			<media:title type="html">liu</media:title>
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			<media:title type="html">weinberg1.jpg</media:title>
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		<title>notes on projects</title>
		<link>http://tally.wordpress.com/2006/10/20/notes-on-projects/</link>
		<comments>http://tally.wordpress.com/2006/10/20/notes-on-projects/#comments</comments>
		<pubDate>Fri, 20 Oct 2006 22:27:36 +0000</pubDate>
		<dc:creator>xil41</dc:creator>
				<category><![CDATA[notes]]></category>

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		<description><![CDATA[A brief procedure: 1. Determin the Kinematics. Match QCD to SCET + NRQCD, basically by writing down the gauge-invariant operators (color singlet or octect) and doing the non-relativistic expansion for quark spinors and etc. in QCD case then matching the results ,to get the hard coefficient at hard-scale. A tree level work(but NOT easy at [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=tally.wordpress.com&amp;blog=376204&amp;post=17&amp;subd=tally&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>A brief procedure:</p>
<p>1. Determin the Kinematics. Match QCD to SCET + NRQCD, basically by writing down the gauge-invariant operators (color singlet or octect) and doing the non-relativistic expansion for quark spinors and etc. in QCD case then matching the results ,to get the hard coefficient at hard-scale.  A tree level work(but NOT easy at all).</p>
<p>2.  Calculate the scattering amplitude at that (hard) scale : factorize, optical theorem. So a loop integral may be needed for singlet case.</p>
<p>3. Use Renormalizatoin Group to run the coefficent to some other scale, by calculating the &#8220;vertex&#8221; corrections. Also need to take operator-mixing into consideration at this step, but it may seem small  in my case. Bunch of integrals here, damned hard piece!!!</p>
<p>4. Interpolating: combine the end-point-result with result away from that.  Maybe some structure functions are needed. No one knows whether these functions are physically correct or not. So maybe, two minus mak e a plus&#8230;.</p>
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		<slash:comments>1</slash:comments>
	
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			<media:title type="html">liu</media:title>
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		<title>Feynman(test embedding Youtube)</title>
		<link>http://tally.wordpress.com/2006/10/20/feynmantest-embedding-youtube/</link>
		<comments>http://tally.wordpress.com/2006/10/20/feynmantest-embedding-youtube/#comments</comments>
		<pubDate>Fri, 20 Oct 2006 03:30:00 +0000</pubDate>
		<dc:creator>xil41</dc:creator>
				<category><![CDATA[Uncategorized]]></category>

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		<description><![CDATA[&#8220;all kinds of interesting questions which a science knowledge only adds to the excitement and mystery and the awe of a flower. It only adds. I don&#8217;t understand how it subtracts.&#8221; 我对理科的兴趣也许真的越来越少了, 不过这不能说明数学啦, 物理啦枯燥无聊; 相反地, 这表现理科是多么有趣:)&#8212;&#8211;你想, 通过12年&#8221;乏味的&#8221;初等数理教育, 另外经过4年&#8221;惨无人道&#8221;的本科高等数理教育, 接着是这些年的研究生生涯, 我依然对理科存有那么一丝丝幻想, 并没有完全泯灭. 可见,&#8221;Science&#8221;是多么有趣, 且令人激动.<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=tally.wordpress.com&amp;blog=376204&amp;post=16&amp;subd=tally&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<span style="text-align:center; display: block;"><a href="http://tally.wordpress.com/2006/10/20/feynmantest-embedding-youtube/"><img src="http://img.youtube.com/vi/zSZNsIFID28/2.jpg" alt="" /></a></span>
<p><span style="display:inline;">&#8220;all kinds of interesting questions which a science knowledge only adds to the excitement and mystery and the awe of a flower. It only adds. I don&#8217;t understand how it subtracts.&#8221;</span></p>
<p>我对理科的兴趣也许真的越来越少了, 不过这不能说明数学啦, 物理啦枯燥无聊; 相反地, 这表现理科是多么有趣:)&#8212;&#8211;你想, 通过12年&#8221;乏味的&#8221;初等数理教育, 另外经过4年&#8221;惨无人道&#8221;的本科高等数理教育, 接着是这些年的研究生生涯, 我依然对理科存有那么一丝丝幻想, 并没有完全泯灭. 可见,&#8221;Science&#8221;是多么有趣, 且令人激动.</p>
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		<title>gnuplot, briefly II plot</title>
		<link>http://tally.wordpress.com/2006/10/14/gnuplot-briefly-ii-plot/</link>
		<comments>http://tally.wordpress.com/2006/10/14/gnuplot-briefly-ii-plot/#comments</comments>
		<pubDate>Sat, 14 Oct 2006 19:45:50 +0000</pubDate>
		<dc:creator>xil41</dc:creator>
				<category><![CDATA[@linux]]></category>

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		<description><![CDATA[gnuplot最重要的当然是作图拉.:) 譬如experimental data存在&#8221;calibration.dat&#8221;里: the1st, 4th, 2nd,5th columns分别是dL , L, dL的实验误差, L的实验误差. 把L作为x, dL作为y来plot, 并且带上两者的实验误差, 用命令: plot &#8220;calibration.dat&#8221; usi 4:1:5:2 w xyerr title &#8220;L v.s dL&#8221; , 其中&#8221;usi 4:1:5:2&#8243;代表用第四,一,二,五列的数据. (默认x,y,xerr,yerr) &#8220;w xyerr&#8221;表示用xyerror bar, &#8220;title &#8230;&#8221;用来作legend. 若打算一次作多种图比如在上面的例子里再作gaussian函数图像, 就用,\来分隔 : plot &#8220;calibration.dat&#8221; usi 4:1:5:2 w xyerr title &#8220;L vs dL&#8221; ,\ 300*exp(-0.01*(x-200)**2) title &#8220;gaussian distribution&#8221; 当然, 可以把所需要作的流程, 如set [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=tally.wordpress.com&amp;blog=376204&amp;post=12&amp;subd=tally&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>gnuplot最重要的当然是作图拉.:) 譬如experimental data存在&#8221;calibration.dat&#8221;里:</p>
<p><a href="http://tally.files.wordpress.com/2006/10/data.png" title="calibration.dat"><img src="http://tally.files.wordpress.com/2006/10/data.png?w=450" alt="calibration.dat" /></a>the1st, 4th, 2nd,5th columns分别是dL , L, dL的实验误差, L的实验误差. 把L作为x, dL作为y来plot, 并且带上两者的实验误差,  用命令: plot  &#8220;calibration.dat&#8221; usi 4:1:5:2 w xyerr title &#8220;L v.s dL&#8221; , 其中&#8221;usi 4:1:5:2&#8243;代表用第四,一,二,五列的数据. (默认x,y,xerr,yerr) &#8220;w xyerr&#8221;表示用xyerror bar, &#8220;title &#8230;&#8221;用来作legend.</p>
<p><a href="https://tally.files.wordpress.com/2006/10/plot.png" title="plot"><img src="https://tally.files.wordpress.com/2006/10/plot.png?w=450" alt="plot" /></a></p>
<p>若打算一次作多种图比如在上面的例子里再作gaussian函数图像, 就用,\来分隔 :</p>
<p>plot &#8220;calibration.dat&#8221; usi 4:1:5:2 w xyerr title &#8220;L vs dL&#8221; ,\</p>
<p>300*exp(-0.01*(x-200)**2) title &#8220;gaussian distribution&#8221;</p>
<p><a href="https://tally.files.wordpress.com/2006/10/vplot.png" title="vplot"><img src="https://tally.files.wordpress.com/2006/10/vplot.png?w=450" alt="vplot" /></a></p>
<p>当然, 可以把所需要作的流程, 如set term, plot &#8220;file&#8221;之类写在一个文件里面,如plot.那么直接在linux下输入gnuplot plot就行了. !!</p>
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			<media:title type="html">liu</media:title>
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			<media:title type="html">calibration.dat</media:title>
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			<media:title type="html">plot</media:title>
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			<media:title type="html">vplot</media:title>
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